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5035431120133 is a prime number
BaseRepresentation
bin100100101000110011100…
…0101010100110100000101
3122211101022212000111222211
41021101213011110310011
51130000030331321013
614413124540223421
71026540451212361
oct111214705246405
918741285014884
105035431120133
111671572659527
12693a9783ab71
132a6aba7042cb
14135a052382a1
158aeb306123d
hex49467154d05

5035431120133 has 2 divisors, whose sum is σ = 5035431120134. Its totient is φ = 5035431120132.

The previous prime is 5035431120101. The next prime is 5035431120151. The reversal of 5035431120133 is 3310211345305.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4045959262849 + 989471857284 = 2011457^2 + 994722^2 .

It is a cyclic number.

It is not a de Polignac number, because 5035431120133 - 25 = 5035431120101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5035431120095 and 5035431120104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5035431120173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517715560066 + 2517715560067.

It is an arithmetic number, because the mean of its divisors is an integer number (2517715560067).

Almost surely, 25035431120133 is an apocalyptic number.

It is an amenable number.

5035431120133 is a deficient number, since it is larger than the sum of its proper divisors (1).

5035431120133 is an equidigital number, since it uses as much as digits as its factorization.

5035431120133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 5035431120133 its reverse (3310211345305), we get a palindrome (8345642465438).

The spelling of 5035431120133 in words is "five trillion, thirty-five billion, four hundred thirty-one million, one hundred twenty thousand, one hundred thirty-three".