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5038400324903 = 11458036393173
BaseRepresentation
bin100100101010001100000…
…0011111100010100100111
3122211122222210002202012212
41021110120003330110213
51130022120440344103
614414335324434035
71030004154065141
oct111243003742447
918748883082185
105038400324903
1116728566a5a70
126945860a891b
132a71718c58ca
14135c07705c91
158b0d8a707d8
hex495180fc527

5038400324903 has 4 divisors (see below), whose sum is σ = 5496436718088. Its totient is φ = 4580363931720.

The previous prime is 5038400324891. The next prime is 5038400324921. The reversal of 5038400324903 is 3094230048305.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5038400324903 - 24 = 5038400324887 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5038400324933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229018196576 + ... + 229018196597.

It is an arithmetic number, because the mean of its divisors is an integer number (1374109179522).

Almost surely, 25038400324903 is an apocalyptic number.

5038400324903 is a deficient number, since it is larger than the sum of its proper divisors (458036393185).

5038400324903 is a wasteful number, since it uses less digits than its factorization.

5038400324903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 458036393184.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 5038400324903 in words is "five trillion, thirty-eight billion, four hundred million, three hundred twenty-four thousand, nine hundred three".

Divisors: 1 11 458036393173 5038400324903