503971241 has 2 divisors, whose sum is σ = 503971242. Its totient is φ = 503971240.

The previous prime is 503971229. The next prime is 503971243. The reversal of 503971241 is 142179305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 349690000 + 154281241 = 18700^2 + 12421^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-503971241 is a prime.

Together with 503971243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 503971198 and 503971207.

It is not a weakly prime, because it can be changed into another prime (503971243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251985620 + 251985621.

It is an arithmetic number, because the mean of its divisors is an integer number (251985621).

Almost surely, 2^503971241 is an apocalyptic number.

It is an amenable number.

503971241 is a deficient number, since it is larger than the sum of its proper divisors (1).

503971241 is an equidigital number, since it uses as much as digits as its factorization.

503971241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7560, while the sum is 32.

The square root of 503971241 is about 22449.3037976682. The cubic root of 503971241 is about 795.7963045577.

The spelling of 503971241 in words is "five hundred three million, nine hundred seventy-one thousand, two hundred forty-one".