Base | Representation |
---|---|
bin | 10110111010110000101000… |
… | …11010010101101011100101 |
3 | 20121102221201122021101100111 |
4 | 23131120110122111223211 |
5 | 23101203024101401013 |
6 | 255104141531413021 |
7 | 13421045515551151 |
oct | 1335302432255345 |
9 | 217387648241314 |
10 | 50397488700133 |
11 | 15070500569753 |
12 | 579b454bb4171 |
13 | 22176029a6763 |
14 | c63374058061 |
15 | 5c5e4ad4973d |
hex | 2dd614695ae5 |
50397488700133 has 2 divisors, whose sum is σ = 50397488700134. Its totient is φ = 50397488700132.
The previous prime is 50397488700113. The next prime is 50397488700179. The reversal of 50397488700133 is 33100788479305.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38350251646564 + 12047237053569 = 6192758^2 + 3470913^2 .
It is a cyclic number.
It is not a de Polignac number, because 50397488700133 - 229 = 50396951829221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50397488700113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25198744350066 + 25198744350067.
It is an arithmetic number, because the mean of its divisors is an integer number (25198744350067).
Almost surely, 250397488700133 is an apocalyptic number.
It is an amenable number.
50397488700133 is a deficient number, since it is larger than the sum of its proper divisors (1).
50397488700133 is an equidigital number, since it uses as much as digits as its factorization.
50397488700133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15240960, while the sum is 58.
The spelling of 50397488700133 in words is "fifty trillion, three hundred ninety-seven billion, four hundred eighty-eight million, seven hundred thousand, one hundred thirty-three".
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