Base | Representation |
---|---|
bin | 1001011000110100… |
… | …00100110000010111 |
3 | 111000020122112021112 |
4 | 10230122010300113 |
5 | 40310220000043 |
6 | 2152040405235 |
7 | 235616202422 |
oct | 45432046027 |
9 | 14006575245 |
10 | 5040000023 |
11 | 2156a48683 |
12 | b87a7681b |
13 | 624225446 |
14 | 35b5149b9 |
15 | 1e7708518 |
hex | 12c684c17 |
5040000023 has 2 divisors, whose sum is σ = 5040000024. Its totient is φ = 5040000022.
The previous prime is 5040000019. The next prime is 5040000037. The reversal of 5040000023 is 3200000405.
It is an a-pointer prime, because the next prime (5040000037) can be obtained adding 5040000023 to its sum of digits (14).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5040000023 - 22 = 5040000019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5039999962 and 5040000007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5040005023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520000011 + 2520000012.
It is an arithmetic number, because the mean of its divisors is an integer number (2520000012).
Almost surely, 25040000023 is an apocalyptic number.
5040000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
5040000023 is an equidigital number, since it uses as much as digits as its factorization.
5040000023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 14.
The square root of 5040000023 is about 70992.9575591833. The cubic root of 5040000023 is about 1714.5237790708.
Adding to 5040000023 its reverse (3200000405), we get a palindrome (8240000428).
The spelling of 5040000023 in words is "five billion, forty million, twenty-three", and thus it is an aban number and an uban number.
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