Base | Representation |
---|---|
bin | 1001011000110111… |
… | …01010110101001111 |
3 | 111000021102202210212 |
4 | 10230123222311033 |
5 | 40310321340002 |
6 | 2152053353035 |
7 | 235622563403 |
oct | 45433526517 |
9 | 14007382725 |
10 | 5040418127 |
11 | 2157203818 |
12 | b8803877b |
13 | 624340844 |
14 | 35b5c3103 |
15 | 1e778c352 |
hex | 12c6ead4f |
5040418127 has 2 divisors, whose sum is σ = 5040418128. Its totient is φ = 5040418126.
The previous prime is 5040418093. The next prime is 5040418153. The reversal of 5040418127 is 7218140405.
It is a happy number.
5040418127 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5040418127 - 26 = 5040418063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5040418093 and 5040418102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5040418157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520209063 + 2520209064.
It is an arithmetic number, because the mean of its divisors is an integer number (2520209064).
Almost surely, 25040418127 is an apocalyptic number.
5040418127 is a deficient number, since it is larger than the sum of its proper divisors (1).
5040418127 is an equidigital number, since it uses as much as digits as its factorization.
5040418127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8960, while the sum is 32.
The square root of 5040418127 is about 70995.9021845627. The cubic root of 5040418127 is about 1714.5711884243.
The spelling of 5040418127 in words is "five billion, forty million, four hundred eighteen thousand, one hundred twenty-seven".
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