Base | Representation |
---|---|
bin | 1110101010110111110… |
… | …11010000000001101111 |
3 | 1210012001100110102012121 |
4 | 13111123323100001233 |
5 | 31224300134314211 |
6 | 1023320422213411 |
7 | 51262625324533 |
oct | 7253373200157 |
9 | 1705040412177 |
10 | 504053432431 |
11 | 18484a02725a |
12 | 81832584267 |
13 | 386bbb59cc3 |
14 | 1a5796c5bc3 |
15 | d1a1910271 |
hex | 755bed006f |
504053432431 has 2 divisors, whose sum is σ = 504053432432. Its totient is φ = 504053432430.
The previous prime is 504053432423. The next prime is 504053432567. The reversal of 504053432431 is 134234350405.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 504053432431 - 23 = 504053432423 is a prime.
It is a super-2 number, since 2×5040534324312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (504053432411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252026716215 + 252026716216.
It is an arithmetic number, because the mean of its divisors is an integer number (252026716216).
Almost surely, 2504053432431 is an apocalyptic number.
504053432431 is a deficient number, since it is larger than the sum of its proper divisors (1).
504053432431 is an equidigital number, since it uses as much as digits as its factorization.
504053432431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 504053432431 its reverse (134234350405), we get a palindrome (638287782836).
The spelling of 504053432431 in words is "five hundred four billion, fifty-three million, four hundred thirty-two thousand, four hundred thirty-one".
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