Base | Representation |
---|---|
bin | 100100101011100011001… |
… | …0010110010111100110111 |
3 | 122211221112111111002212020 |
4 | 1021113012102302330313 |
5 | 1130044112301014023 |
6 | 14415541345324223 |
7 | 1030136460220155 |
oct | 111270622627467 |
9 | 18757474432766 |
10 | 5041323454263 |
11 | 1674016732358 |
12 | 695061036673 |
13 | 2a75193a4255 |
14 | 136003a1c3d5 |
15 | 8b20a4ccde3 |
hex | 495c64b2f37 |
5041323454263 has 4 divisors (see below), whose sum is σ = 6721764605688. Its totient is φ = 3360882302840.
The previous prime is 5041323454243. The next prime is 5041323454333. The reversal of 5041323454263 is 3624543231405.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5041323454263 - 217 = 5041323323191 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5041323454243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 840220575708 + ... + 840220575713.
It is an arithmetic number, because the mean of its divisors is an integer number (1680441151422).
Almost surely, 25041323454263 is an apocalyptic number.
5041323454263 is a deficient number, since it is larger than the sum of its proper divisors (1680441151425).
5041323454263 is a wasteful number, since it uses less digits than its factorization.
5041323454263 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1680441151424.
The product of its (nonzero) digits is 1036800, while the sum is 42.
Adding to 5041323454263 its reverse (3624543231405), we get a palindrome (8665866685668).
The spelling of 5041323454263 in words is "five trillion, forty-one billion, three hundred twenty-three million, four hundred fifty-four thousand, two hundred sixty-three".
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