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50415310051 = 153493284599
BaseRepresentation
bin101110111100111111…
…001001010011100011
311211010112022002220121
4232330333021103203
51311222304410201
635054355021111
73433224031141
oct567477112343
9154115262817
1050415310051
111a4211456a7
12992bb9a797
1349a5b11b12
14262395c591
1514a107e9a1
hexbbcfc94e3

50415310051 has 4 divisors (see below), whose sum is σ = 50418610000. Its totient is φ = 50412010104.

The previous prime is 50415310027. The next prime is 50415310093. The reversal of 50415310051 is 15001351405.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15001351405 = 53000270281.

It is a cyclic number.

It is not a de Polignac number, because 50415310051 - 211 = 50415308003 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50415309998 and 50415310025.

It is not an unprimeable number, because it can be changed into a prime (50415310651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1626951 + ... + 1657648.

It is an arithmetic number, because the mean of its divisors is an integer number (12604652500).

Almost surely, 250415310051 is an apocalyptic number.

50415310051 is a deficient number, since it is larger than the sum of its proper divisors (3299949).

50415310051 is a wasteful number, since it uses less digits than its factorization.

50415310051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3299948.

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 50415310051 its reverse (15001351405), we get a palindrome (65416661456).

The spelling of 50415310051 in words is "fifty billion, four hundred fifteen million, three hundred ten thousand, fifty-one".

Divisors: 1 15349 3284599 50415310051