Search a number
-
+
504386024893 is a prime number
BaseRepresentation
bin1110101011011111011…
…11111111010110111101
31210012220112021212021221
413111233233333112331
531230440310244033
61023413422553341
751304104321052
oct7255757772675
91705815255257
10504386024893
111849aa841963
1281905a38851
1338742a29a8a
141a5ab941029
15d1c0c0b12d
hex756fbff5bd

504386024893 has 2 divisors, whose sum is σ = 504386024894. Its totient is φ = 504386024892.

The previous prime is 504386024827. The next prime is 504386024959. The reversal of 504386024893 is 398420683405.

It is a balanced prime because it is at equal distance from previous prime (504386024827) and next prime (504386024959).

It can be written as a sum of positive squares in only one way, i.e., 435952511289 + 68433513604 = 660267^2 + 261598^2 .

It is a cyclic number.

It is not a de Polignac number, because 504386024893 - 221 = 504383927741 is a prime.

It is a super-2 number, since 2×5043860248932 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 504386024893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (504386028893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252193012446 + 252193012447.

It is an arithmetic number, because the mean of its divisors is an integer number (252193012447).

Almost surely, 2504386024893 is an apocalyptic number.

It is an amenable number.

504386024893 is a deficient number, since it is larger than the sum of its proper divisors (1).

504386024893 is an equidigital number, since it uses as much as digits as its factorization.

504386024893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4976640, while the sum is 52.

The spelling of 504386024893 in words is "five hundred four billion, three hundred eighty-six million, twenty-four thousand, eight hundred ninety-three".