Base | Representation |
---|---|
bin | 101110111110101001… |
… | …101110100110000101 |
3 | 11211012110212121101111 |
4 | 232332221232212011 |
5 | 1311301433000203 |
6 | 35101233525021 |
7 | 3434013356650 |
oct | 567651564605 |
9 | 154173777344 |
10 | 50443250053 |
11 | 1a435999409 |
12 | 9939413771 |
13 | 49ab845271 |
14 | 2627552897 |
15 | 14a374d26d |
hex | bbea6e985 |
50443250053 has 4 divisors (see below), whose sum is σ = 57649428640. Its totient is φ = 43237071468.
The previous prime is 50443250027. The next prime is 50443250057. The reversal of 50443250053 is 35005234405.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 50443250053 - 229 = 49906379141 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50443249997 and 50443250024.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50443250057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3603089283 + ... + 3603089296.
It is an arithmetic number, because the mean of its divisors is an integer number (14412357160).
Almost surely, 250443250053 is an apocalyptic number.
It is an amenable number.
50443250053 is a deficient number, since it is larger than the sum of its proper divisors (7206178587).
50443250053 is an equidigital number, since it uses as much as digits as its factorization.
50443250053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7206178586.
The product of its (nonzero) digits is 36000, while the sum is 31.
Adding to 50443250053 its reverse (35005234405), we get a palindrome (85448484458).
The spelling of 50443250053 in words is "fifty billion, four hundred forty-three million, two hundred fifty thousand, fifty-three".
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