Base | Representation |
---|---|
bin | 101111000010001111… |
… | …000000101011101001 |
3 | 11211100122222021000211 |
4 | 233002033000223221 |
5 | 1311412324330423 |
6 | 35111222101121 |
7 | 3435343302241 |
oct | 570217005351 |
9 | 154318867024 |
10 | 50503355113 |
11 | 1a466911212 |
12 | 995557a7a1 |
13 | 49bb12aca3 |
14 | 263151ab21 |
15 | 14a8b7210d |
hex | bc23c0ae9 |
50503355113 has 2 divisors, whose sum is σ = 50503355114. Its totient is φ = 50503355112.
The previous prime is 50503355069. The next prime is 50503355141. The reversal of 50503355113 is 31155330505.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34004466409 + 16498888704 = 184403^2 + 128448^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50503355113 is a prime.
It is not a weakly prime, because it can be changed into another prime (50503355143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25251677556 + 25251677557.
It is an arithmetic number, because the mean of its divisors is an integer number (25251677557).
Almost surely, 250503355113 is an apocalyptic number.
It is an amenable number.
50503355113 is a deficient number, since it is larger than the sum of its proper divisors (1).
50503355113 is an equidigital number, since it uses as much as digits as its factorization.
50503355113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16875, while the sum is 31.
Adding to 50503355113 its reverse (31155330505), we get a palindrome (81658685618).
The spelling of 50503355113 in words is "fifty billion, five hundred three million, three hundred fifty-five thousand, one hundred thirteen".
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