Base | Representation |
---|---|
bin | 1001011010011010… |
… | …10010010111011001 |
3 | 111001011220121001002 |
4 | 10231031102113121 |
5 | 40322134100423 |
6 | 2153240234345 |
7 | 236141255552 |
oct | 45515222731 |
9 | 14034817032 |
10 | 5053425113 |
11 | 21635880a0 |
12 | b9046b9b5 |
13 | 626c45c99 |
14 | 35d20b329 |
15 | 1e89ab228 |
hex | 12d3525d9 |
5053425113 has 4 divisors (see below), whose sum is σ = 5512827408. Its totient is φ = 4594022820.
The previous prime is 5053425089. The next prime is 5053425127. The reversal of 5053425113 is 3115243505.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5053425113 - 218 = 5053162969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5053425133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229701131 + ... + 229701152.
It is an arithmetic number, because the mean of its divisors is an integer number (1378206852).
Almost surely, 25053425113 is an apocalyptic number.
It is an amenable number.
5053425113 is a deficient number, since it is larger than the sum of its proper divisors (459402295).
5053425113 is a wasteful number, since it uses less digits than its factorization.
5053425113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 459402294.
The product of its (nonzero) digits is 9000, while the sum is 29.
The square root of 5053425113 is about 71087.4469438874. The cubic root of 5053425113 is about 1716.0447598051.
Adding to 5053425113 its reverse (3115243505), we get a palindrome (8168668618).
The spelling of 5053425113 in words is "five billion, fifty-three million, four hundred twenty-five thousand, one hundred thirteen".
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