Base | Representation |
---|---|
bin | 1110101101100111111… |
… | …00000000010010110101 |
3 | 1210022212020221002121111 |
4 | 13112303330000102311 |
5 | 31240311141301031 |
6 | 1024123130515021 |
7 | 51344335212541 |
oct | 7266374002265 |
9 | 1708766832544 |
10 | 505530025141 |
11 | 18543757a209 |
12 | 81b84b95a71 |
13 | 38895a44cbb |
14 | 1a679854a21 |
15 | d23b3841b1 |
hex | 75b3f004b5 |
505530025141 has 2 divisors, whose sum is σ = 505530025142. Its totient is φ = 505530025140.
The previous prime is 505530025139. The next prime is 505530025163. The reversal of 505530025141 is 141520035505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 470430002641 + 35100022500 = 685879^2 + 187350^2 .
It is a cyclic number.
It is not a de Polignac number, because 505530025141 - 21 = 505530025139 is a prime.
Together with 505530025139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (505530025541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252765012570 + 252765012571.
It is an arithmetic number, because the mean of its divisors is an integer number (252765012571).
Almost surely, 2505530025141 is an apocalyptic number.
It is an amenable number.
505530025141 is a deficient number, since it is larger than the sum of its proper divisors (1).
505530025141 is an equidigital number, since it uses as much as digits as its factorization.
505530025141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 505530025141 in words is "five hundred five billion, five hundred thirty million, twenty-five thousand, one hundred forty-one".
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