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5056527141137 is a prime number
BaseRepresentation
bin100100110010101000010…
…0000010000100100010001
3122220101210001220102102002
41021211100200100210101
51130321231422004022
614430534141203345
71031215312350653
oct111452040204421
918811701812362
105056527141137
11167a50882532a
12697ba4860555
132a8aa0198784
14136a46d046d3
158b7ea129092
hex49950810911

5056527141137 has 2 divisors, whose sum is σ = 5056527141138. Its totient is φ = 5056527141136.

The previous prime is 5056527141131. The next prime is 5056527141139. The reversal of 5056527141137 is 7311417256505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2834158782016 + 2222368359121 = 1683496^2 + 1490761^2 .

It is a cyclic number.

It is not a de Polignac number, because 5056527141137 - 24 = 5056527141121 is a prime.

Together with 5056527141139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5056527141091 and 5056527141100.

It is not a weakly prime, because it can be changed into another prime (5056527141131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2528263570568 + 2528263570569.

It is an arithmetic number, because the mean of its divisors is an integer number (2528263570569).

Almost surely, 25056527141137 is an apocalyptic number.

It is an amenable number.

5056527141137 is a deficient number, since it is larger than the sum of its proper divisors (1).

5056527141137 is an equidigital number, since it uses as much as digits as its factorization.

5056527141137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 882000, while the sum is 47.

The spelling of 5056527141137 in words is "five trillion, fifty-six billion, five hundred twenty-seven million, one hundred forty-one thousand, one hundred thirty-seven".