Base | Representation |
---|---|
bin | 1110101111010011010… |
… | …11010110111100100101 |
3 | 1210102012002110102112022 |
4 | 13113221223112330211 |
5 | 31244132444144031 |
6 | 1024352415232525 |
7 | 51405563560502 |
oct | 7275153267445 |
9 | 1712162412468 |
10 | 506431631141 |
11 | 18585a4a9137 |
12 | 82196b18745 |
13 | 389aa781687 |
14 | 1a7234ac4a9 |
15 | d2905cb97b |
hex | 75e9ad6f25 |
506431631141 has 2 divisors, whose sum is σ = 506431631142. Its totient is φ = 506431631140.
The previous prime is 506431631063. The next prime is 506431631143. The reversal of 506431631141 is 141136134605.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 377499648100 + 128931983041 = 614410^2 + 359071^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-506431631141 is a prime.
Together with 506431631143, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (506431631143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253215815570 + 253215815571.
It is an arithmetic number, because the mean of its divisors is an integer number (253215815571).
Almost surely, 2506431631141 is an apocalyptic number.
It is an amenable number.
506431631141 is a deficient number, since it is larger than the sum of its proper divisors (1).
506431631141 is an equidigital number, since it uses as much as digits as its factorization.
506431631141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 35.
Adding to 506431631141 its reverse (141136134605), we get a palindrome (647567765746).
The spelling of 506431631141 in words is "five hundred six billion, four hundred thirty-one million, six hundred thirty-one thousand, one hundred forty-one".
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