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50712513080743 is a prime number
BaseRepresentation
bin10111000011111011011010…
…10100111110110110100111
320122120001212020020000200201
423201331231110332312213
523121333211322040433
6255505001253251331
713452600230605453
oct1341755524766647
9218501766200621
1050712513080743
111518206861a528
125830512033b47
13223b2284096b7
14c746da729663
155ce237536a7d
hex2e1f6d53eda7

50712513080743 has 2 divisors, whose sum is σ = 50712513080744. Its totient is φ = 50712513080742.

The previous prime is 50712513080741. The next prime is 50712513080813. The reversal of 50712513080743 is 34708031521705.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 50712513080743 - 21 = 50712513080741 is a prime.

Together with 50712513080741, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 50712513080693 and 50712513080702.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50712513080741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25356256540371 + 25356256540372.

It is an arithmetic number, because the mean of its divisors is an integer number (25356256540372).

Almost surely, 250712513080743 is an apocalyptic number.

50712513080743 is a deficient number, since it is larger than the sum of its proper divisors (1).

50712513080743 is an equidigital number, since it uses as much as digits as its factorization.

50712513080743 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 705600, while the sum is 46.

The spelling of 50712513080743 in words is "fifty trillion, seven hundred twelve billion, five hundred thirteen million, eighty thousand, seven hundred forty-three".