Base | Representation |
---|---|
bin | 100101000000011010011… |
… | …0101010110101100110001 |
3 | 200000020011222112121112120 |
4 | 1022000310311112230301 |
5 | 1131312342141232210 |
6 | 14452311303344453 |
7 | 1033313661651660 |
oct | 112006465265461 |
9 | 20006158477476 |
10 | 5086127680305 |
11 | 1691018531541 |
12 | 6a1885a52129 |
13 | 2ab80987a7c9 |
14 | 138254288dd7 |
15 | 8c47db49270 |
hex | 4a034d56b31 |
5086127680305 has 128 divisors (see below), whose sum is σ = 9443394616320. Its totient is φ = 2289606758400.
The previous prime is 5086127680297. The next prime is 5086127680327. The reversal of 5086127680305 is 5030867216805.
It is a happy number.
5086127680305 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5086127680305 - 23 = 5086127680297 is a prime.
It is a super-3 number, since 3×50861276803053 (a number of 39 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2273636647 + ... + 2273638883.
It is an arithmetic number, because the mean of its divisors is an integer number (73776520440).
Almost surely, 25086127680305 is an apocalyptic number.
It is an amenable number.
5086127680305 is a deficient number, since it is larger than the sum of its proper divisors (4357266936015).
5086127680305 is a wasteful number, since it uses less digits than its factorization.
5086127680305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3419.
The product of its (nonzero) digits is 2419200, while the sum is 51.
The spelling of 5086127680305 in words is "five trillion, eighty-six billion, one hundred twenty-seven million, six hundred eighty thousand, three hundred five".
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