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50866230508453 is a prime number
BaseRepresentation
bin10111001000011001101111…
…00110011011101110100101
320200002202122001200102201001
423210030313212123232211
523131343020002232303
6300103342415233301
713466651416310413
oct1344146746335645
9220082561612631
1050866230508453
111523127a051088
125856271818831
13224c884ba2109
14c7bd1dab62b3
155d323267131d
hex2e433799bba5

50866230508453 has 2 divisors, whose sum is σ = 50866230508454. Its totient is φ = 50866230508452.

The previous prime is 50866230508399. The next prime is 50866230508531. The reversal of 50866230508453 is 35480503266805.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33307130340289 + 17559100168164 = 5771233^2 + 4190358^2 .

It is a cyclic number.

It is not a de Polignac number, because 50866230508453 - 237 = 50728791554981 is a prime.

It is a super-2 number, since 2×508662305084532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50866230508394 and 50866230508403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50866230508253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25433115254226 + 25433115254227.

It is an arithmetic number, because the mean of its divisors is an integer number (25433115254227).

Almost surely, 250866230508453 is an apocalyptic number.

It is an amenable number.

50866230508453 is a deficient number, since it is larger than the sum of its proper divisors (1).

50866230508453 is an equidigital number, since it uses as much as digits as its factorization.

50866230508453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736000, while the sum is 55.

The spelling of 50866230508453 in words is "fifty trillion, eight hundred sixty-six billion, two hundred thirty million, five hundred eight thousand, four hundred fifty-three".