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509938683943 = 1339226052611
BaseRepresentation
bin1110110101110101011…
…01101101000000100111
31210202020111121011112211
413122322231231000213
531323323300341233
61030132415424251
751561520203313
oct7327255550047
91722214534484
10509938683943
1118729a102887
12829b5525087
133911921a250
141a977184b43
15d3e842d5cd
hex76bab6d027

509938683943 has 4 divisors (see below), whose sum is σ = 549164736568. Its totient is φ = 470712631320.

The previous prime is 509938683901. The next prime is 509938683997. The reversal of 509938683943 is 349386839905.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-509938683943 is a prime.

It is a super-2 number, since 2×5099386839432 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (509938687943) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19613026293 + ... + 19613026318.

It is an arithmetic number, because the mean of its divisors is an integer number (137291184142).

Almost surely, 2509938683943 is an apocalyptic number.

509938683943 is a deficient number, since it is larger than the sum of its proper divisors (39226052625).

509938683943 is a wasteful number, since it uses less digits than its factorization.

509938683943 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39226052624.

The product of its (nonzero) digits is 151165440, while the sum is 67.

The spelling of 509938683943 in words is "five hundred nine billion, nine hundred thirty-eight million, six hundred eighty-three thousand, nine hundred forty-three".

Divisors: 1 13 39226052611 509938683943