50994901 has 2 divisors, whose sum is σ = 50994902. Its totient is φ = 50994900.

The previous prime is 50994871. The next prime is 50994913. The reversal of 50994901 is 10949905.

50994901 = 5049² + 5050².

50994901 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25502500 + 25492401 = 5050^2 + 5049^2 .

It is a cyclic number.

It is not a de Polignac number, because 50994901 - 2¹¹ = 50992853 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50994941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25497450 + 25497451.

It is an arithmetic number, because the mean of its divisors is an integer number (25497451).

Almost surely, 2^50994901 is an apocalyptic number.

50994901 is the 5050-th centered square number.

It is an amenable number.

50994901 is a deficient number, since it is larger than the sum of its proper divisors (1).

50994901 is an equidigital number, since it uses as much as digits as its factorization.

50994901 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14580, while the sum is 37.

The square root of 50994901 is about 7141.0714182117. The cubic root of 50994901 is about 370.8306175060.

It can be divided in two parts, 5099 and 4901, that added together give a 4-th power (10000 = 10⁴).

The spelling of 50994901 in words is "fifty million, nine hundred ninety-four thousand, nine hundred one".