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51000000013 = 192684210527
BaseRepresentation
bin101111011111110101…
…100011111000001101
311212122021111102202101
4233133311203320031
51313422000000023
635232402555101
73453553563454
oct573765437015
9155567442671
1051000000013
111a6a1196946
129a73968a91
134a69ca9c01
14267b47bb9b
1514d75761ad
hexbdfd63e0d

51000000013 has 4 divisors (see below), whose sum is σ = 53684210560. Its totient is φ = 48315789468.

The previous prime is 50999999957. The next prime is 51000000041. The reversal of 51000000013 is 31000000015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51000000013 - 225 = 50966445581 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51000000043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1342105245 + ... + 1342105282.

It is an arithmetic number, because the mean of its divisors is an integer number (13421052640).

Almost surely, 251000000013 is an apocalyptic number.

It is an amenable number.

51000000013 is a deficient number, since it is larger than the sum of its proper divisors (2684210547).

51000000013 is a wasteful number, since it uses less digits than its factorization.

51000000013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2684210546.

The product of its (nonzero) digits is 15, while the sum is 10.

Adding to 51000000013 its reverse (31000000015), we get a palindrome (82000000028).

The spelling of 51000000013 in words is "fifty-one billion, thirteen", and thus it is an aban number and an uban number.

Divisors: 1 19 2684210527 51000000013