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510000005213 is a prime number
BaseRepresentation
bin1110110101111100101…
…11101000000001011101
31210202101202222121111222
413122332113220001131
531323440000131323
61030142450023125
751563163342446
oct7327627500135
91722352877458
10510000005213
11187320786416
1282a11b77aa5
1339128b3a71a
141a9813882cd
15d3ed9e29c8
hex76be5e805d

510000005213 has 2 divisors, whose sum is σ = 510000005214. Its totient is φ = 510000005212.

The previous prime is 510000005167. The next prime is 510000005231. The reversal of 510000005213 is 312500000015.

Together with next prime (510000005231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 504743465209 + 5256540004 = 710453^2 + 72502^2 .

It is a cyclic number.

It is not a de Polignac number, because 510000005213 - 212 = 510000001117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 510000005191 and 510000005200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (510000005293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255000002606 + 255000002607.

It is an arithmetic number, because the mean of its divisors is an integer number (255000002607).

Almost surely, 2510000005213 is an apocalyptic number.

It is an amenable number.

510000005213 is a deficient number, since it is larger than the sum of its proper divisors (1).

510000005213 is an equidigital number, since it uses as much as digits as its factorization.

510000005213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150, while the sum is 17.

Adding to 510000005213 its reverse (312500000015), we get a palindrome (822500005228).

The spelling of 510000005213 in words is "five hundred ten billion, five thousand, two hundred thirteen".