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5100241 = 6776123
BaseRepresentation
bin10011011101001011010001
3100121010012211
4103131023101
52301201431
6301152121
761231336
oct23351321
910533184
105100241
112973983
12185b641
1310975c3
1496a98d
156ab2b1
hex4dd2d1

5100241 has 4 divisors (see below), whose sum is σ = 5176432. Its totient is φ = 5024052.

The previous prime is 5100239. The next prime is 5100253. The reversal of 5100241 is 1420015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1420015 = 5284003.

It is a cyclic number.

It is not a de Polignac number, because 5100241 - 21 = 5100239 is a prime.

It is an Ulam number.

It is a Duffinian number.

5100241 is a lucky number.

It is not an unprimeable number, because it can be changed into a prime (5100211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37995 + ... + 38128.

It is an arithmetic number, because the mean of its divisors is an integer number (1294108).

Almost surely, 25100241 is an apocalyptic number.

It is an amenable number.

5100241 is a deficient number, since it is larger than the sum of its proper divisors (76191).

5100241 is an equidigital number, since it uses as much as digits as its factorization.

5100241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76190.

The product of its (nonzero) digits is 40, while the sum is 13.

The square root of 5100241 is about 2258.3713157938. The cubic root of 5100241 is about 172.1327733597.

Adding to 5100241 its reverse (1420015), we get a palindrome (6520256).

The spelling of 5100241 in words is "five million, one hundred thousand, two hundred forty-one".

Divisors: 1 67 76123 5100241