Base | Representation |
---|---|
bin | 101111011111111111… |
… | …110000001100010101 |
3 | 11212122110112011212220 |
4 | 233133333300030111 |
5 | 1313423141000033 |
6 | 35232540132553 |
7 | 3453615362265 |
oct | 573777601425 |
9 | 155573464786 |
10 | 51002671893 |
11 | 1a6a2751308 |
12 | 9a74837159 |
13 | 4a6a7040c4 |
14 | 267b9757a5 |
15 | 14d7902bb3 |
hex | bdfff0315 |
51002671893 has 4 divisors (see below), whose sum is σ = 68003562528. Its totient is φ = 34001781260.
The previous prime is 51002671891. The next prime is 51002671901. The reversal of 51002671893 is 39817620015.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51002671893 - 21 = 51002671891 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51002671891) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8500445313 + ... + 8500445318.
It is an arithmetic number, because the mean of its divisors is an integer number (17000890632).
Almost surely, 251002671893 is an apocalyptic number.
It is an amenable number.
51002671893 is a deficient number, since it is larger than the sum of its proper divisors (17000890635).
51002671893 is a wasteful number, since it uses less digits than its factorization.
51002671893 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17000890634.
The product of its (nonzero) digits is 90720, while the sum is 42.
The spelling of 51002671893 in words is "fifty-one billion, two million, six hundred seventy-one thousand, eight hundred ninety-three".
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