Base | Representation |
---|---|
bin | 101111100000011011… |
… | …111011111101110011 |
3 | 11212122222102112122221 |
4 | 233200123323331303 |
5 | 1313432033411042 |
6 | 35233402341511 |
7 | 3454035233344 |
oct | 574033737563 |
9 | 155588375587 |
10 | 51010060147 |
11 | 1a6a6938202 |
12 | 9a771ba897 |
13 | 4a6c0bcc57 |
14 | 267c93a0cb |
15 | 14d83b1d67 |
hex | be06fbf73 |
51010060147 has 4 divisors (see below), whose sum is σ = 51304916160. Its totient is φ = 50715204136.
The previous prime is 51010060117. The next prime is 51010060177. The reversal of 51010060147 is 74106001015.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74106001015 = 5 ⋅14821200203.
It is an interprime number because it is at equal distance from previous prime (51010060117) and next prime (51010060177).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51010060147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51010060117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147427747 + ... + 147428092.
It is an arithmetic number, because the mean of its divisors is an integer number (12826229040).
Almost surely, 251010060147 is an apocalyptic number.
51010060147 is a deficient number, since it is larger than the sum of its proper divisors (294856013).
51010060147 is a wasteful number, since it uses less digits than its factorization.
51010060147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 294856012.
The product of its (nonzero) digits is 840, while the sum is 25.
The spelling of 51010060147 in words is "fifty-one billion, ten million, sixty thousand, one hundred forty-seven".
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