Base | Representation |
---|---|
bin | 100101000111010111001… |
… | …0011100101101100001111 |
3 | 200001122200222112222210020 |
4 | 1022032232103211230033 |
5 | 1132033422420113210 |
6 | 14503220144313223 |
7 | 1034352534162534 |
oct | 112165623455417 |
9 | 20048628488706 |
10 | 5101050551055 |
11 | 1697386063178 |
12 | 6a474b612813 |
13 | 2b0047430044 |
14 | 138c6c152d8b |
15 | 8ca53cc5770 |
hex | 4a3ae4e5b0f |
5101050551055 has 32 divisors (see below), whose sum is σ = 8196331852800. Its totient is φ = 2709011367552.
The previous prime is 5101050551053. The next prime is 5101050551083. The reversal of 5101050551055 is 5501550501015.
It is not a de Polignac number, because 5101050551055 - 21 = 5101050551053 is a prime.
It is a super-3 number, since 3×51010505510553 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5101050551053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 78073741 + ... + 78139049.
It is an arithmetic number, because the mean of its divisors is an integer number (256135370400).
Almost surely, 25101050551055 is an apocalyptic number.
5101050551055 is a deficient number, since it is larger than the sum of its proper divisors (3095281301745).
5101050551055 is a wasteful number, since it uses less digits than its factorization.
5101050551055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87343.
The product of its (nonzero) digits is 15625, while the sum is 33.
The spelling of 5101050551055 in words is "five trillion, one hundred one billion, fifty million, five hundred fifty-one thousand, fifty-five".
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