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5101433 = 22922277
BaseRepresentation
bin10011011101011101111001
3100121011211222
4103131131321
52301221213
6301201425
761234661
oct23353571
910534758
105101433
112974867
121860275
131097ccc
1496b1a1
156ab808
hex4dd779

5101433 has 4 divisors (see below), whose sum is σ = 5123940. Its totient is φ = 5078928.

The previous prime is 5101417. The next prime is 5101441. The reversal of 5101433 is 3341015.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3341015 = 5668203.

It can be written as a sum of positive squares in 2 ways, for example, as 4528384 + 573049 = 2128^2 + 757^2 .

It is a cyclic number.

It is not a de Polignac number, because 5101433 - 24 = 5101417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5101403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10910 + ... + 11367.

It is an arithmetic number, because the mean of its divisors is an integer number (1280985).

Almost surely, 25101433 is an apocalyptic number.

It is an amenable number.

5101433 is a deficient number, since it is larger than the sum of its proper divisors (22507).

5101433 is a wasteful number, since it uses less digits than its factorization.

5101433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22506.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 5101433 is about 2258.6352073763. The cubic root of 5101433 is about 172.1461822870.

Adding to 5101433 its reverse (3341015), we get a palindrome (8442448).

The spelling of 5101433 in words is "five million, one hundred one thousand, four hundred thirty-three".

Divisors: 1 229 22277 5101433