Base | Representation |
---|---|
bin | 101111100001101000… |
… | …000000000110001101 |
3 | 11212201100221121000111 |
4 | 233201220000012031 |
5 | 1314002140000023 |
6 | 35235354000021 |
7 | 3454366562146 |
oct | 574150000615 |
9 | 155640847014 |
10 | 51030000013 |
11 | 1a707117333 |
12 | 9a81a16011 |
13 | 4a73281ba5 |
14 | 268144aacd |
15 | 14da00000d |
hex | be1a0018d |
51030000013 has 2 divisors, whose sum is σ = 51030000014. Its totient is φ = 51030000012.
The previous prime is 51029999983. The next prime is 51030000029. The reversal of 51030000013 is 31000003015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34255346724 + 16774653289 = 185082^2 + 129517^2 .
It is a cyclic number.
It is not a de Polignac number, because 51030000013 - 229 = 50493129101 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51029999948 and 51030000002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51030000083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25515000006 + 25515000007.
It is an arithmetic number, because the mean of its divisors is an integer number (25515000007).
Almost surely, 251030000013 is an apocalyptic number.
It is an amenable number.
51030000013 is a deficient number, since it is larger than the sum of its proper divisors (1).
51030000013 is an equidigital number, since it uses as much as digits as its factorization.
51030000013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 13.
Adding to 51030000013 its reverse (31000003015), we get a palindrome (82030003028).
The spelling of 51030000013 in words is "fifty-one billion, thirty million, thirteen", and thus it is an aban number and an uban number.
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