Base | Representation |
---|---|
bin | 101111100001101011… |
… | …111110110100010111 |
3 | 11212201102220121012122 |
4 | 233201223332310113 |
5 | 1314002421341401 |
6 | 35235432210155 |
7 | 3454411466021 |
oct | 574153766427 |
9 | 155642817178 |
10 | 51031043351 |
11 | 1a70776a1a2 |
12 | 9a8223995b |
13 | 4a73558a52 |
14 | 268163d011 |
15 | 14da15921b |
hex | be1afed17 |
51031043351 has 2 divisors, whose sum is σ = 51031043352. Its totient is φ = 51031043350.
The previous prime is 51031043333. The next prime is 51031043363. The reversal of 51031043351 is 15334013015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51031043351 - 222 = 51026849047 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 51031043351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51031043551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25515521675 + 25515521676.
It is an arithmetic number, because the mean of its divisors is an integer number (25515521676).
Almost surely, 251031043351 is an apocalyptic number.
51031043351 is a deficient number, since it is larger than the sum of its proper divisors (1).
51031043351 is an equidigital number, since it uses as much as digits as its factorization.
51031043351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 51031043351 its reverse (15334013015), we get a palindrome (66365056366).
The spelling of 51031043351 in words is "fifty-one billion, thirty-one million, forty-three thousand, three hundred fifty-one".
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