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51041113 is a prime number
BaseRepresentation
bin1100001010110…
…1001101011001
310120001011020121
43002231031121
5101031303423
65021553241
71156561624
oct302551531
9116034217
1051041113
11268a1a42
1215115821
13a761256
146ac8dbb
15473345d
hex30ad359

51041113 has 2 divisors, whose sum is σ = 51041114. Its totient is φ = 51041112.

The previous prime is 51041063. The next prime is 51041141. The reversal of 51041113 is 31114015.

51041113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36578304 + 14462809 = 6048^2 + 3803^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51041113 is a prime.

It is not a weakly prime, because it can be changed into another prime (51041143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25520556 + 25520557.

It is an arithmetic number, because the mean of its divisors is an integer number (25520557).

Almost surely, 251041113 is an apocalyptic number.

It is an amenable number.

51041113 is a deficient number, since it is larger than the sum of its proper divisors (1).

51041113 is an equidigital number, since it uses as much as digits as its factorization.

51041113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 51041113 is about 7144.3063344176. The cubic root of 51041113 is about 370.9426002745.

Adding to 51041113 its reverse (31114015), we get a palindrome (82155128).

The spelling of 51041113 in words is "fifty-one million, forty-one thousand, one hundred thirteen".