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51041141 is a prime number
BaseRepresentation
bin1100001010110…
…1001101110101
310120001011021122
43002231031311
5101031304031
65021553325
71156561664
oct302551565
9116034248
1051041141
11268a1a68
1215115845
13a761278
146ac8ddb
15473347b
hex30ad375

51041141 has 2 divisors, whose sum is σ = 51041142. Its totient is φ = 51041140.

The previous prime is 51041113. The next prime is 51041143. The reversal of 51041141 is 14114015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42315025 + 8726116 = 6505^2 + 2954^2 .

It is a cyclic number.

It is not a de Polignac number, because 51041141 - 218 = 50778997 is a prime.

Together with 51041143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51041143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25520570 + 25520571.

It is an arithmetic number, because the mean of its divisors is an integer number (25520571).

Almost surely, 251041141 is an apocalyptic number.

It is an amenable number.

51041141 is a deficient number, since it is larger than the sum of its proper divisors (1).

51041141 is an equidigital number, since it uses as much as digits as its factorization.

51041141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 51041141 is about 7144.3082940198. The cubic root of 51041141 is about 370.9426681047.

Adding to 51041141 its reverse (14114015), we get a palindrome (65155156).

The spelling of 51041141 in words is "fifty-one million, forty-one thousand, one hundred forty-one".