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51042120000 = 263543113721
BaseRepresentation
bin101111100010010110…
…001111000101000000
311212202012202100111220
4233202112033011000
51314013240320000
635240505435040
73454604601324
oct574226170500
9155665670456
1051042120000
111a712a45253
129a85a9ba80
134a75936691
142682cc3984
1514db0e61a0
hexbe258f140

51042120000 has 280 divisors, whose sum is σ = 174213633792. Its totient is φ = 13171200000.

The previous prime is 51042119993. The next prime is 51042120091. The reversal of 51042120000 is 2124015.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 3713140 + ... + 3726860.

Almost surely, 251042120000 is an apocalyptic number.

51042120000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 51042120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (87106816896).

51042120000 is an abundant number, since it is smaller than the sum of its proper divisors (123171513792).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51042120000 is a wasteful number, since it uses less digits than its factorization.

51042120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13787 (or 13762 counting only the distinct ones).

The product of its (nonzero) digits is 80, while the sum is 15.

Adding to 51042120000 its reverse (2124015), we get a palindrome (51044244015).

The spelling of 51042120000 in words is "fifty-one billion, forty-two million, one hundred twenty thousand".