Base | Representation |
---|---|
bin | 100101001000110110000… |
… | …0000100101101000101011 |
3 | 200001221220210100101210110 |
4 | 1022101230000211220223 |
5 | 1132111432202204011 |
6 | 14504504040345403 |
7 | 1034524441456413 |
oct | 112215400455053 |
9 | 20057823311713 |
10 | 5104233241131 |
11 | 1698769663352 |
12 | 6a5299475263 |
13 | 2b043391a9cb |
14 | 139090b13643 |
15 | 8cb8d404ba6 |
hex | 4a46c025a2b |
5104233241131 has 16 divisors (see below), whose sum is σ = 7101610813440. Its totient is φ = 3254841786240.
The previous prime is 5104233241127. The next prime is 5104233241141. The reversal of 5104233241131 is 1311423324015.
It is not a de Polignac number, because 5104233241131 - 22 = 5104233241127 is a prime.
It is a super-2 number, since 2×51042332411312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5104233241141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8309190 + ... + 8902308.
It is an arithmetic number, because the mean of its divisors is an integer number (443850675840).
Almost surely, 25104233241131 is an apocalyptic number.
5104233241131 is a deficient number, since it is larger than the sum of its proper divisors (1997377572309).
5104233241131 is a wasteful number, since it uses less digits than its factorization.
5104233241131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 717866.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 5104233241131 its reverse (1311423324015), we get a palindrome (6415656565146).
The spelling of 5104233241131 in words is "five trillion, one hundred four billion, two hundred thirty-three million, two hundred forty-one thousand, one hundred thirty-one".
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