Base | Representation |
---|---|
bin | 100101001001001100111… |
… | …0001010111000010001111 |
3 | 200002000220022000122110222 |
4 | 1022102121301113002033 |
5 | 1132120020224013403 |
6 | 14505112144221555 |
7 | 1034552453354603 |
oct | 112223161270217 |
9 | 20060808018428 |
10 | 5105001001103 |
11 | 1699022a83823 |
12 | 6a547260a8bb |
13 | 2b05269c3153 |
14 | 139124a89503 |
15 | 8cbd5a0e338 |
hex | 4a499c5708f |
5105001001103 has 2 divisors, whose sum is σ = 5105001001104. Its totient is φ = 5105001001102.
The previous prime is 5105001001019. The next prime is 5105001001127. The reversal of 5105001001103 is 3011001005015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5105001001103 - 210 = 5105001000079 is a prime.
It is a super-2 number, since 2×51050010011032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5105001001193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552500500551 + 2552500500552.
It is an arithmetic number, because the mean of its divisors is an integer number (2552500500552).
Almost surely, 25105001001103 is an apocalyptic number.
5105001001103 is a deficient number, since it is larger than the sum of its proper divisors (1).
5105001001103 is an equidigital number, since it uses as much as digits as its factorization.
5105001001103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75, while the sum is 17.
Adding to 5105001001103 its reverse (3011001005015), we get a palindrome (8116002006118).
The spelling of 5105001001103 in words is "five trillion, one hundred five billion, one million, one thousand, one hundred three".
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