Base | Representation |
---|---|
bin | 100101001001001101110… |
… | …0101001001001011011111 |
3 | 200002000222102010200112100 |
4 | 1022102123211021023133 |
5 | 1132120101011244210 |
6 | 14505115150540143 |
7 | 1034553302350344 |
oct | 112223345111337 |
9 | 20060872120470 |
10 | 5105031353055 |
11 | 1699039124687 |
12 | 6a5480807653 |
13 | 2b053008c39a |
14 | 139128b0a7cb |
15 | 8cbd85075c0 |
hex | 4a49b9492df |
5105031353055 has 24 divisors (see below), whose sum is σ = 8871824752128. Its totient is φ = 2715574545216.
The previous prime is 5105031353047. The next prime is 5105031353089. The reversal of 5105031353055 is 5503531305015.
5105031353055 is a `hidden beast` number, since 5 + 10 + 50 + 3 + 13 + 530 + 55 = 666.
It is not a de Polignac number, because 5105031353055 - 23 = 5105031353047 is a prime.
It is a super-2 number, since 2×51050313530552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 148083472 + ... + 148117941.
It is an arithmetic number, because the mean of its divisors is an integer number (369659364672).
Almost surely, 25105031353055 is an apocalyptic number.
5105031353055 is a deficient number, since it is larger than the sum of its proper divisors (3766793399073).
5105031353055 is a wasteful number, since it uses less digits than its factorization.
5105031353055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 296201807 (or 296201804 counting only the distinct ones).
The product of its (nonzero) digits is 84375, while the sum is 36.
The spelling of 5105031353055 in words is "five trillion, one hundred five billion, thirty-one million, three hundred fifty-three thousand, fifty-five".
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