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51100041 = 31011371231
BaseRepresentation
bin1100001011101…
…1100110001001
310120011011002010
43002323212021
5101040200131
65023130133
71160225466
oct302734611
9116134063
1051100041
1126932243
1215143949
13a782015
146b0266d
154745b46
hex30bb989

51100041 has 16 divisors (see below), whose sum is σ = 69366528. Its totient is φ = 33456000.

The previous prime is 51100033. The next prime is 51100057. The reversal of 51100041 is 14000115.

It is a happy number.

51100041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 51100041 - 23 = 51100033 is a prime.

It is a super-2 number, since 2×511000412 = 5222428380403362, which contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (51104041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40896 + ... + 42126.

It is an arithmetic number, because the mean of its divisors is an integer number (4335408).

Almost surely, 251100041 is an apocalyptic number.

It is an amenable number.

51100041 is a deficient number, since it is larger than the sum of its proper divisors (18266487).

51100041 is a wasteful number, since it uses less digits than its factorization.

51100041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1472.

The product of its (nonzero) digits is 20, while the sum is 12.

The square root of 51100041 is about 7148.4292680280. The cubic root of 51100041 is about 371.0852989572.

Adding to 51100041 its reverse (14000115), we get a palindrome (65100156).

The spelling of 51100041 in words is "fifty-one million, one hundred thousand, forty-one".

Divisors: 1 3 101 137 303 411 1231 3693 13837 41511 124331 168647 372993 505941 17033347 51100041