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51100115 = 511284463
BaseRepresentation
bin1100001011101…
…1100111010011
310120011011011212
43002323213103
5101040200430
65023130335
71160225633
oct302734723
9116134155
1051100115
1126932300
12151439ab
13a782071
146b026c3
154745b95
hex30bb9d3

51100115 has 12 divisors (see below), whose sum is σ = 67402272. Its totient is φ = 37163280.

The previous prime is 51100057. The next prime is 51100157.

51100115 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 51100115 - 214 = 51083731 is a prime.

It is a super-2 number, since 2×511001152 = 5222443506026450, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 51100115.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 41627 + ... + 42836.

It is an arithmetic number, because the mean of its divisors is an integer number (5616856).

Almost surely, 251100115 is an apocalyptic number.

51100115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

51100115 is a deficient number, since it is larger than the sum of its proper divisors (16302157).

51100115 is a wasteful number, since it uses less digits than its factorization.

51100115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84490 (or 84479 counting only the distinct ones).

The product of its (nonzero) digits is 25, while the sum is 14.

The square root of 51100115 is about 7148.4344439884. The cubic root of 51100115 is about 371.0854780849.

It can be divided in two parts, 51100 and 115, that added together give a palindrome (51215).

The spelling of 51100115 in words is "fifty-one million, one hundred thousand, one hundred fifteen".

Divisors: 1 5 11 55 121 605 84463 422315 929093 4645465 10220023 51100115