Base | Representation |
---|---|
bin | 10111001111001101011010… |
… | …01000001000100101101110 |
3 | 20200221010100221210200121021 |
4 | 23213212231020020211232 |
5 | 23144211031402324324 |
6 | 300403024220124354 |
7 | 13522601604445621 |
oct | 1347465510104556 |
9 | 220833327720537 |
10 | 51100130511214 |
11 | 15311497550094 |
12 | 589366a3966ba |
13 | 226894c565605 |
14 | c8938c165db8 |
15 | 5d9371ce0ae4 |
hex | 2e79ad20896e |
51100130511214 has 4 divisors (see below), whose sum is σ = 76650195766824. Its totient is φ = 25550065255606.
The previous prime is 51100130511191. The next prime is 51100130511247. The reversal of 51100130511214 is 41211503100115.
51100130511214 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×511001305112142 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12775032627802 + ... + 12775032627805.
It is an arithmetic number, because the mean of its divisors is an integer number (19162548941706).
Almost surely, 251100130511214 is an apocalyptic number.
51100130511214 is a deficient number, since it is larger than the sum of its proper divisors (25550065255610).
51100130511214 is a wasteful number, since it uses less digits than its factorization.
51100130511214 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25550065255609.
The product of its (nonzero) digits is 600, while the sum is 25.
Adding to 51100130511214 its reverse (41211503100115), we get a palindrome (92311633611329).
The spelling of 51100130511214 in words is "fifty-one trillion, one hundred billion, one hundred thirty million, five hundred eleven thousand, two hundred fourteen".
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