Base | Representation |
---|---|
bin | 1110110111110100011… |
… | …11000110000101111001 |
3 | 1210211222202221020221111 |
4 | 13123322033012011321 |
5 | 31333014111331131 |
6 | 1030430245440321 |
7 | 51630110515210 |
oct | 7337217060571 |
9 | 1724882836844 |
10 | 511004402041 |
11 | 187796732641 |
12 | 830524100a1 |
13 | 39258c56c83 |
14 | 1aa3891c077 |
15 | d45bc91ab1 |
hex | 76fa3c6179 |
511004402041 has 16 divisors (see below), whose sum is σ = 633440183040. Its totient is φ = 402184235520.
The previous prime is 511004402011. The next prime is 511004402047. The reversal of 511004402041 is 140204400115.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-511004402041 is a prime.
It is a super-2 number, since 2×5110044020412 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (511004402047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52362861 + ... + 52372618.
It is an arithmetic number, because the mean of its divisors is an integer number (39590011440).
Almost surely, 2511004402041 is an apocalyptic number.
It is an amenable number.
511004402041 is a deficient number, since it is larger than the sum of its proper divisors (122435780999).
511004402041 is a wasteful number, since it uses less digits than its factorization.
511004402041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104735544.
The product of its (nonzero) digits is 640, while the sum is 22.
Adding to 511004402041 its reverse (140204400115), we get a palindrome (651208802156).
The spelling of 511004402041 in words is "five hundred eleven billion, four million, four hundred two thousand, forty-one".
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