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5110140455471 is a prime number
BaseRepresentation
bin100101001011100110000…
…0110110100101000101111
3200002112011110210222110202
41022113030012310220233
51132211031424033341
614511322140424115
71035124021120562
oct112271406645057
920075143728422
105110140455471
1116a022007a977
126a646784803b
132b0b656ca8cc
1413949148c4d9
158cdd6d1079b
hex4a5cc1b4a2f

5110140455471 has 2 divisors, whose sum is σ = 5110140455472. Its totient is φ = 5110140455470.

The previous prime is 5110140455449. The next prime is 5110140455503. The reversal of 5110140455471 is 1745540410115.

It is a happy number.

5110140455471 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5110140455471 is a prime.

It is a super-3 number, since 3×51101404554713 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5110140455671) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555070227735 + 2555070227736.

It is an arithmetic number, because the mean of its divisors is an integer number (2555070227736).

Almost surely, 25110140455471 is an apocalyptic number.

5110140455471 is a deficient number, since it is larger than the sum of its proper divisors (1).

5110140455471 is an equidigital number, since it uses as much as digits as its factorization.

5110140455471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56000, while the sum is 38.

Adding to 5110140455471 its reverse (1745540410115), we get a palindrome (6855680865586).

The spelling of 5110140455471 in words is "five trillion, one hundred ten billion, one hundred forty million, four hundred fifty-five thousand, four hundred seventy-one".