Base | Representation |
---|---|
bin | 100101001011101001011… |
… | …0111111110010101010111 |
3 | 200002112110101110211010220 |
4 | 1022113102313332111113 |
5 | 1132211300011103133 |
6 | 14511341314245423 |
7 | 1035126600220533 |
oct | 112272267762527 |
9 | 20075411424126 |
10 | 5110254003543 |
11 | 16a0279185257 |
12 | 6a6499886873 |
13 | 2b0b830a5c10 |
14 | 1394a25a8bc3 |
15 | 8cde1c8e5b3 |
hex | 4a5d2dfe557 |
5110254003543 has 32 divisors (see below), whose sum is σ = 7769928499200. Its totient is φ = 2959597487616.
The previous prime is 5110254003539. The next prime is 5110254003599. The reversal of 5110254003543 is 3453004520115.
It is not a de Polignac number, because 5110254003543 - 22 = 5110254003539 is a prime.
It is a super-2 number, since 2×51102540035432 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110254002543) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10583338 + ... + 11055656.
It is an arithmetic number, because the mean of its divisors is an integer number (242810265600).
Almost surely, 25110254003543 is an apocalyptic number.
5110254003543 is a deficient number, since it is larger than the sum of its proper divisors (2659674495657).
5110254003543 is a wasteful number, since it uses less digits than its factorization.
5110254003543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 488671.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 5110254003543 its reverse (3453004520115), we get a palindrome (8563258523658).
The spelling of 5110254003543 in words is "five trillion, one hundred ten billion, two hundred fifty-four million, three thousand, five hundred forty-three".
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