Base | Representation |
---|---|
bin | 100101001011101010110… |
… | …0111110110111001110111 |
3 | 200002112120121020021221022 |
4 | 1022113111213312321313 |
5 | 1132211343312013310 |
6 | 14511350042411355 |
7 | 1035131000142161 |
oct | 112272547667167 |
9 | 20075517207838 |
10 | 5110300110455 |
11 | 16a02a2207041 |
12 | 6a64b1200b5b |
13 | 2b0b8c7ca307 |
14 | 1394a876b931 |
15 | 8cde5d4aa55 |
hex | 4a5d59f6e77 |
5110300110455 has 16 divisors (see below), whose sum is σ = 6139294560000. Its totient is φ = 4083618147840.
The previous prime is 5110300110407. The next prime is 5110300110457. The reversal of 5110300110455 is 5540110030115.
It is not a de Polignac number, because 5110300110455 - 226 = 5110233001591 is a prime.
It is a super-2 number, since 2×51103001104552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110300110457) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43788521 + ... + 43905069.
It is an arithmetic number, because the mean of its divisors is an integer number (383705910000).
Almost surely, 25110300110455 is an apocalyptic number.
5110300110455 is a deficient number, since it is larger than the sum of its proper divisors (1028994449545).
5110300110455 is a wasteful number, since it uses less digits than its factorization.
5110300110455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126394.
The product of its (nonzero) digits is 1500, while the sum is 26.
The spelling of 5110300110455 in words is "five trillion, one hundred ten billion, three hundred million, one hundred ten thousand, four hundred fifty-five".
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