5110343341 has 4 divisors (see below), whose sum is σ = 5379308800. Its totient is φ = 4841377884.

The previous prime is 5110343333. The next prime is 5110343347. The reversal of 5110343341 is 1433430115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5110343341 - 2³ = 5110343333 is a prime.

It is a super-2 number, since 2×5110343341² = 52231218125806084562, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5110343347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134482701 + ... + 134482738.

It is an arithmetic number, because the mean of its divisors is an integer number (1344827200).

Almost surely, 2^5110343341 is an apocalyptic number.

It is an amenable number.

5110343341 is a deficient number, since it is larger than the sum of its proper divisors (268965459).

5110343341 is a wasteful number, since it uses less digits than its factorization.

5110343341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 268965458.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 5110343341 is about 71486.6654768566. The cubic root of 5110343341 is about 1722.4634950200.

Adding to 5110343341 its reverse (1433430115), we get a palindrome (6543773456).

The spelling of 5110343341 in words is "five billion, one hundred ten million, three hundred forty-three thousand, three hundred forty-one".