Base | Representation |
---|---|
bin | 11110011101011… |
… | …101111110000101 |
3 | 1022121121121000202 |
4 | 132131131332011 |
5 | 2021311311123 |
6 | 122413220245 |
7 | 15443531441 |
oct | 3635357605 |
9 | 1277547022 |
10 | 511041413 |
11 | 242518a83 |
12 | 123191685 |
13 | 81b4c98c |
14 | 4bc2b821 |
15 | 2ece9a28 |
hex | 1e75df85 |
511041413 has 2 divisors, whose sum is σ = 511041414. Its totient is φ = 511041412.
The previous prime is 511041407. The next prime is 511041449. The reversal of 511041413 is 314140115.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 349802209 + 161239204 = 18703^2 + 12698^2 .
It is a cyclic number.
It is not a de Polignac number, because 511041413 - 210 = 511040389 is a prime.
It is a super-2 number, since 2×5110414132 = 522326651602073138, which contains 22 as substring.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (511046413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255520706 + 255520707.
It is an arithmetic number, because the mean of its divisors is an integer number (255520707).
Almost surely, 2511041413 is an apocalyptic number.
It is an amenable number.
511041413 is a deficient number, since it is larger than the sum of its proper divisors (1).
511041413 is an equidigital number, since it uses as much as digits as its factorization.
511041413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
The square root of 511041413 is about 22606.2250939868. The cubic root of 511041413 is about 799.5004240323.
Adding to 511041413 its reverse (314140115), we get a palindrome (825181528).
The spelling of 511041413 in words is "five hundred eleven million, forty-one thousand, four hundred thirteen".
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