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51108131 is a prime number
BaseRepresentation
bin1100001011110…
…1100100100011
310120011120011202
43002331210203
5101040430011
65023231415
71160261204
oct302754443
9116146152
1051108131
1126938328
121514856b
13a7858c9
146b055ab
15474823b
hex30bd923

51108131 has 2 divisors, whose sum is σ = 51108132. Its totient is φ = 51108130.

The previous prime is 51108107. The next prime is 51108151. The reversal of 51108131 is 13180115.

51108131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (51108151) can be obtained adding 51108131 to its sum of digits (20).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51108131 - 26 = 51108067 is a prime.

It is a super-2 number, since 2×511081312 = 5224082108626322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (51108151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25554065 + 25554066.

It is an arithmetic number, because the mean of its divisors is an integer number (25554066).

Almost surely, 251108131 is an apocalyptic number.

51108131 is a deficient number, since it is larger than the sum of its proper divisors (1).

51108131 is an equidigital number, since it uses as much as digits as its factorization.

51108131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 20.

The square root of 51108131 is about 7148.9951042087. The cubic root of 51108131 is about 371.1048809483.

Adding to 51108131 its reverse (13180115), we get a palindrome (64288246).

The spelling of 51108131 in words is "fifty-one million, one hundred eight thousand, one hundred thirty-one".