Base | Representation |
---|---|
bin | 1001100001010010… |
… | …01000001100100111 |
3 | 111012012100111120122 |
4 | 10300221020030213 |
5 | 40431412231033 |
6 | 2203055352155 |
7 | 240441152255 |
oct | 46051101447 |
9 | 14165314518 |
10 | 5111055143 |
11 | 219306a417 |
12 | ba782265b |
13 | 635b732ac |
14 | 366b2d5d5 |
15 | 1eda91a98 |
hex | 130a48327 |
5111055143 has 4 divisors (see below), whose sum is σ = 5137537488. Its totient is φ = 5084572800.
The previous prime is 5111055139. The next prime is 5111055167. The reversal of 5111055143 is 3415501115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5111055143 - 22 = 5111055139 is a prime.
It is a super-2 number, since 2×51110551432 = 52245769349573500898, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5111045143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13240883 + ... + 13241268.
It is an arithmetic number, because the mean of its divisors is an integer number (1284384372).
Almost surely, 25111055143 is an apocalyptic number.
5111055143 is a deficient number, since it is larger than the sum of its proper divisors (26482345).
5111055143 is a wasteful number, since it uses less digits than its factorization.
5111055143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26482344.
The product of its (nonzero) digits is 1500, while the sum is 26.
The square root of 5111055143 is about 71491.6438683571. The cubic root of 5111055143 is about 1722.5434632961.
Adding to 5111055143 its reverse (3415501115), we get a palindrome (8526556258).
The spelling of 5111055143 in words is "five billion, one hundred eleven million, fifty-five thousand, one hundred forty-three".
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