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5111214551 is a prime number
BaseRepresentation
bin1001100001010011…
…01111000111010111
3111012012122121020122
410300221233013113
540431432331201
62203103022155
7240442415102
oct46051570727
914165577218
105111214551
112193169163
12ba789a95b
13635bcaa11
14366b71739
151edac3e1b
hex130a6f1d7

5111214551 has 2 divisors, whose sum is σ = 5111214552. Its totient is φ = 5111214550.

The previous prime is 5111214539. The next prime is 5111214613. The reversal of 5111214551 is 1554121115.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5111214551 is a prime.

It is a super-2 number, since 2×51112145512 = 52249028372708263202, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5111214551.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5111264551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555607275 + 2555607276.

It is an arithmetic number, because the mean of its divisors is an integer number (2555607276).

Almost surely, 25111214551 is an apocalyptic number.

5111214551 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111214551 is an equidigital number, since it uses as much as digits as its factorization.

5111214551 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1000, while the sum is 26.

The square root of 5111214551 is about 71492.7587312170. The cubic root of 5111214551 is about 1722.5613711674.

Adding to 5111214551 its reverse (1554121115), we get a palindrome (6665335666).

The spelling of 5111214551 in words is "five billion, one hundred eleven million, two hundred fourteen thousand, five hundred fifty-one".