51113031433 has 8 divisors (see below), whose sum is σ = 51259944960. Its totient is φ = 50966225760.

The previous prime is 51113031391. The next prime is 51113031439. The reversal of 51113031433 is 33413031115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51113031433 - 2¹⁷ = 51112900361 is a prime.

It is a super-2 number, since 2×51113031433² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51113031398 and 51113031407.

It is not an unprimeable number, because it can be changed into a prime (51113031439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 975288 + ... + 1026358.

It is an arithmetic number, because the mean of its divisors is an integer number (6407493120).

Almost surely, 2^51113031433 is an apocalyptic number.

It is an amenable number.

51113031433 is a deficient number, since it is larger than the sum of its proper divisors (146913527).

51113031433 is a wasteful number, since it uses less digits than its factorization.

51113031433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53927.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 51113031433 its reverse (33413031115), we get a palindrome (84526062548).

The spelling of 51113031433 in words is "fifty-one billion, one hundred thirteen million, thirty-one thousand, four hundred thirty-three".