Base | Representation |
---|---|
bin | 100101001100001001010… |
… | …1111001110110010111111 |
3 | 200002122020001121010011202 |
4 | 1022120102233032302333 |
5 | 1132220443304003003 |
6 | 14512035511210115 |
7 | 1035165260334413 |
oct | 112302257166277 |
9 | 20078201533152 |
10 | 5111325453503 |
11 | 16a0778a6a495 |
12 | 6a673867693b |
13 | 2b0cc406b889 |
14 | 1395649d4d43 |
15 | 8ce55d86088 |
hex | 4a612bcecbf |
5111325453503 has 2 divisors, whose sum is σ = 5111325453504. Its totient is φ = 5111325453502.
The previous prime is 5111325453433. The next prime is 5111325453569. The reversal of 5111325453503 is 3053545231115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5111325453503 - 216 = 5111325387967 is a prime.
It is a super-2 number, since 2×51113254535032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5111325453583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555662726751 + 2555662726752.
It is an arithmetic number, because the mean of its divisors is an integer number (2555662726752).
Almost surely, 25111325453503 is an apocalyptic number.
5111325453503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111325453503 is an equidigital number, since it uses as much as digits as its factorization.
5111325453503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 5111325453503 in words is "five trillion, one hundred eleven billion, three hundred twenty-five million, four hundred fifty-three thousand, five hundred three".
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